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Sequences and Series Review

Try each problem first. You don’t need to finish everything.

Core path ~55 min Full sheet ~1 h 50 min

Recommended: K1–K5, then one A and one T problem

K = Knowledge & Understanding · A = Application · T = Thinking · Boss = Challenge

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Core Skills (K)

Arithmetic · Geometric · Recursive · Arithmetic Series · Geometric Series

K1 Arithmetic Sequences

  1. a)
    The first four terms of an arithmetic sequence are graphed below. Each grid square is 1 unit. Determine dd and t20t_{20}.
    Four separate points plotted against n: (1, -5), (2, -2), (3, 1) and (4, 4).ntₙ12345−6−4−2135
  2. b)
    Determine the general term of 41,34,27,…41, 34, 27, \dots and find t15t_{15}.
  3. c)
    Which term of 150,143,136,…150, 143, 136, \dots is equal to 33?
Stuck? Peek at a hint

Find dd as a later term minus the term before it. Keep (n−1)d(n-1)d in brackets when dd is negative.

K2 Geometric Sequences

  1. a)
    Determine rr and t10t_{10} for 3,−6,12,…3, -6, 12, \dots
  2. b)
    A geometric sequence has a=5a=5 and r=3r=3. Determine its general term and evaluate t6t_6.
  3. c)
    Which term of 4,12,36,…4, 12, 36, \dots is equal to 29162916?
Stuck? Peek at a hint

Divide a term by the one before it to find rr. In arn−1ar^{n-1}, raise rr to the power first, then multiply by aa.

K3 Recursive Sequences

  1. a)
    Write t3t_3 to t6t_6 for t1=2t_1=2, t2=5t_2=5, tn=tn−1+tn−2t_n=t_{n-1}+t_{n-2}.
  2. b)
    Determine the explicit formula for t1=9t_1=9, tn=tn−1+4t_n=t_{n-1}+4.
  3. c)
    For the sequence in the table, state whether it is arithmetic, geometric or neither. Then write a recursive formula for it.
    nn 1122334455
    tnt_n 3377151531316363
Stuck? Peek at a hint

Write out the first few terms before looking for a pattern. For (c), compute both the differences and the ratios of consecutive terms.

K4 Arithmetic Series

  1. a)
    Find the sum 7+11+15+⋯+877+11+15+\dots+87.
  2. b)
    Find S25S_{25} for the arithmetic series with a=−6a=-6 and d=3d=3.
  3. c)
    An arithmetic series has a=3a=3 and d=4d=4. How many terms add to 300300?
Stuck? Peek at a hint

Find nn from the general term before using the sum formula. Inside 2a+(n−1)d2a+(n-1)d, multiply by dd before adding.

K5 Geometric Series

  1. a)
    Find S8S_8 for 2+6+18+…2+6+18+\dots
  2. b)
    How many terms of 5+10+20+…5+10+20+\dots add to 12751275?
  3. c)
    Find S6S_6 for 64−32+16−…64-32+16-\dots
Stuck? Peek at a hint

Identify aa and rr first, including the sign of rr. In the sum formula, compute rnr^n before anything else.

Real World (A)

Savings · Chain Messages · Bouncing Ball

A1 Laptop Fund

Noah saves $5.00 in the first week of the year. Each week after that, he saves $0.50 more than the week before.

  1. a)
    How much does Noah save in week 20?
  2. b)
    How much has he saved in total after 20 weeks?
  3. c)
    Noah wants $1000 for a laptop by the end of the year (52 weeks). Solve Sn=1000S_n=1000. Can he reach his goal in time? How much does he have after 52 weeks?
Stuck? Peek at a hint

Write both amounts in dollars before choosing aa and dd.

A2 Chain Message

In round 1 of a chain message, 4 people receive it. In each later round, every person who received it in the previous round sends it to 3 people who have not seen it yet.

  1. a)
    Write the general term for the number of new people who receive the message in round nn. How many receive it in round 6?
  2. b)
    In which round do more than 100 000100\,000 new people first receive the message?
  3. c)
    Ontario has about 16 million people. In which round does the formula first give more new people than that? What does this mean for the model?
Stuck? Peek at a hint

Round 1 has 303^0 in its formula, so check which exponent goes with which round.

A3 Bouncing Ball

A ball is dropped from a height of 10 m. After each bounce, it rises to 60% of the height it fell from.

  1. a)
    Find the height of the 4th rebound.
  2. b)
    Find the total vertical distance the ball has travelled when it hits the ground for the 6th time. Round to the nearest hundredth of a metre.
  3. c)
    The formula gives a positive rebound height for every bounce, so it predicts the ball never stops. Find the first rebound lower than 1 cm, and say what this means for the model.
Stuck? Peek at a hint

Sketch the ball's path for the first three bounces and label every distance it travels.

Think It Through (T)

Error Analysis · Building Sequences

T1 Spot the Flaw

A student expands (3x−2)4(3x-2)^4:
"Row 4 of Pascal's triangle is 1,4,6,4,11, 4, 6, 4, 1, so (3x−2)4=(3x)4+4(3x)3(−2)+6(3x)2(−2)2+4(3x)(−2)3+(−2)4(3x-2)^4=(3x)^4+4(3x)^3(-2)+6(3x)^2(-2)^2+4(3x)(-2)^3+(-2)^4, which is 3x4−24x3+72x2−96x+163x^4-24x^3+72x^2-96x+16."

  1. a)
    Evaluate (3x−2)4(3x-2)^4 and the student's answer at x=1x=1. What does the result prove?
  2. b)
    Identify the error and write the correct expansion.
  3. c)
    Explain why the student's xx-term and constant term are correct anyway.
Stuck? Peek at a hint

For (b), compare (3x)2(3x)^2 with (3x)(3x)(3x)(3x).

T2 Build It Backwards

Build each sequence from the information given. Some parts have more than one answer.

  1. a)
    An arithmetic sequence has t5=23t_5=23 and t12=51t_{12}=51. Determine its general term.
  2. b)
    A geometric sequence has t2=6t_2=6 and t4=54t_4=54. Determine every possible general term.
  3. c)
    Find every value of xx for which 2,x,182, x, 18 is a geometric sequence, and every value for which it is an arithmetic sequence.
Stuck? Peek at a hint

Count the steps between the two given terms: from t5t_5 to t12t_{12}, dd is added 7 times.

Boss Level

Optional challenge

Neither 3 nor 5

Use arithmetic series to answer each part.

  1. a)
    Find the sum of all multiples of 3 from 3 to 300.
  2. b)
    Find the sum of all multiples of 5 from 5 to 300.
  3. c)
    Find the sum of all integers from 1 to 300 that are divisible by neither 3 nor 5.
Stuck? Peek at a hint

For (c), start from 1+2+⋯+3001+2+\dots+300, then decide which multiples to remove.

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Answer key

Final answers only. Try first, then check.

Core Skills

K1
  • a) d=3d=3, t20=52t_{20}=52
  • b) tn=48−7nt_n=48-7n; t15=−57t_{15}=-57
  • c) t22t_{22} (the 22nd term)
K2
  • a) r=−2r=-2, t10=−1536t_{10}=-1536
  • b) tn=5(3)n−1t_n=5(3)^{n-1}; t6=1215t_6=1215
  • c) t7t_7 (the 7th term)
K3
  • a) 7,12,19,317, 12, 19, 31
  • b) tn=4n+5t_n=4n+5
  • c) Neither; t1=3t_1=3, tn=2tn−1+1t_n=2t_{n-1}+1
K4
  • a) 987987 (2121 terms)
  • b) 750750
  • c) 1212 terms
K5
  • a) 65606560
  • b) 88 terms
  • c) 4242

Real World

A1
  • a) $14.50
  • b) $195.00
  • c) n2+19n−4000=0n^2+19n-4000=0 gives n≈54.5n\approx54.5 (the negative root is not a number of weeks). He first passes $1000 in week 55, so no. After 52 weeks he has $923.00.
A2
  • a) tn=4(3)n−1t_n=4(3)^{n-1}; 972972 people
  • b) Round 11 (236 196236\,196 people; round 10 has 78 73278\,732)
  • c) Round 15 (about 19.119.1 million). That is more new people than live in Ontario, so the model must break down before round 15: the message runs out of people who have not seen it.
A3
  • a) 1.2961.296 m
  • b) 37.6737.67 m
  • c) The 14th rebound (about 0.780.78 cm). Past this point the model no longer describes a real ball: a real ball stops bouncing after finitely many bounces.

Think It Through

T1
  • a) 11 and −29-29. The two expressions disagree at x=1x=1, so the expansion is wrong.
  • b) (3x)k(3x)^k was written as 3xk3x^k; it is 3kxk3^kx^k. Correct: 81x4−216x3+216x2−96x+1681x^4-216x^3+216x^2-96x+16
  • c) The xx-term contains (3x)1=3x(3x)^1=3x, and the constant term contains no factor 3x3x, so writing 3xk3x^k for (3x)k(3x)^k changes nothing there.
T2
  • a) tn=4n+3t_n=4n+3 (a=7a=7, d=4d=4)
  • b) tn=2(3)n−1t_n=2(3)^{n-1} or tn=−2(−3)n−1t_n=-2(-3)^{n-1}
  • c) Geometric: x=6x=6 or x=−6x=-6. Arithmetic: x=10x=10.

Boss Level

Boss
  • a) 15 15015\,150
  • b) 91509150
  • c) 24 00024\,000

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Sequences and Series Cheat Sheet

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Most testedFind the sum of the first 1010 terms of 3+6+12+⋯3+6+12+\cdots. (card 6)

1Arithmetic sequences

tn=a+(n−1)dd=tn−tn−1t_n=a+(n-1)d\qquad d=t_n-t_{n-1}

UseCheck dd for every consecutive pair. Finding nn: solve for it; it must be a positive integer.

Trapa=20a=20, d=−3d=-3: t15=20+14(−3)=−22t_{15}=20+14(-3)=-22, not 20+14−320+14-3.

Trap$45 000 now, ++$1500 a year: after 1010 years is 45 000+10(1500)45\,000+10(1500), the 1111th term.

2Geometric sequences

tn=arn−1r=tntn−1t_n=ar^{n-1}\qquad r=\dfrac{t_n}{t_{n-1}}

UseCheck rr for every pair. The exponent applies to rr only. Growth of 4%4\%: r=1.04r=1.04.

Trapa=5a=5, r=2r=2: t4=5(2)3=40t_4=5(2)^3=40, not (5⋅2)3=1000(5\cdot2)^3=1000.

Trap486=6(3)n−1486=6(3)^{n-1}: 3n−1=81=343^{n-1}=81=3^4, so n−1=4n-1=4 and n=5n=5.

3Recursive formulas

t1=a,  tn=tn−1+dt1=a,  tn=r tn−1t_1=a,\ \ t_n=t_{n-1}+d\qquad t_1=a,\ \ t_n=r\,t_{n-1}

UseTo go explicit, keep the same aa and dd (or rr) and keep n−1n-1.

Examplet1=15t_1=15, tn=tn−1−6t_n=t_{n-1}-6: tn=15−6(n−1)=21−6nt_n=15-6(n-1)=21-6n.

Trapt1=1t_1=1, t2=3t_2=3, tn=tn−1+tn−2t_n=t_{n-1}+t_{n-2} gives 1,3,4,7,111,3,4,7,11: start from the given terms, not Fibonacci's.

4Classifying

UseTest differences and ratios. Constant difference: arithmetic. Constant ratio: geometric. Neither: look for another rule.

Trap4,8,16,324, 8, 16, 32: the differences change, but the ratio is 22, so it is geometric, not "neither".

5Arithmetic series

Sn=n2(t1+tn)=n2[2a+(n−1)d]S_n=\dfrac n2(t_1+t_n)=\dfrac n2\left[2a+(n-1)d\right]

UseFind nn first. Solving for nn can give a quadratic: keep only positive integers. Use one unit (dollars or cents).

Example5+8+⋯+625+8+\cdots+62: 62=5+3(n−1)62=5+3(n-1), n=20n=20, S20=10(67)=670S_{20}=10(67)=670.

TrapIn 2a+(n−1)d2a+(n-1)d, multiply (n−1)d(n-1)d first, then add 2a2a.

6Geometric series

Sn=a(rn−1)r−1,r≠1S_n=\dfrac{a(r^n-1)}{r-1},\quad r\ne1

UseBouncing ball: the first drop, then each bounce counts up and down.

Example3+6+12+⋯3+6+12+\cdots: S10=3(210−1)/(2−1)=3069S_{10}=3(2^{10}-1)/(2-1)=3069.

Trap3n=2433^n=243 gives n=5n=5, not 243/3=81243/3=81: find the power.

TrapA ball dropped 88 m, rebounding to 3/43/4: by the 4th landing it travels 8+2(6+4.5+3.375)=35.758+2(6+4.5+3.375)=35.75 m.

7Pascal's triangle

UseRow nn (1,n,…,n,11, n, \dots, n, 1) gives the coefficients of (a+b)n(a+b)^n. Powers of aa fall as powers of bb rise; each term's exponents add to nn.

Example(x+2)3=x3+3x2(2)+3x(2)2+23=x3+6x2+12x+8(x+2)^3=x^3+3x^2(2)+3x(2)^2+2^3=x^3+6x^2+12x+8.

TrapIn (2x−3)3(2x-3)^3, (2x)3=8x3(2x)^3=8x^3, not 2x32x^3: the power applies to the coefficient too.

Which sequence?

Constant difference Arithmetic
Constant ratio Geometric
Each term from the two before Recursive

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