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Exponential and Logarithmic Functions Review

Try each problem first. You don’t need to finish everything.

Core path ~55 min Full sheet ~1 h 45 min

Recommended: K1–K5, then one A and one T problem

K = Knowledge & Understanding · A = Application · T = Thinking · Boss = Challenge

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Show your work on separate paper. Show your work in the dot-grid space.

Core Skills (K)

Exponential Graphs · Transformations · Equivalent Bases · Evaluating Logs · Log Laws

K1 From a Table

The table shows values of an exponential function f(x)=a⋅bxf(x)=a\cdot b^x.

xx 11223344
f(x)f(x) 2020551.251.250.31250.3125
  1. a)
    Determine aa and bb.
  2. b)
    State whether ff shows growth or decay. Then state its domain, its range and the equation of its asymptote.
  3. c)
    Evaluate f(−2)f(-2) and f(12)f\left(\frac{1}{2}\right).
Stuck? Peek at a hint

Divide each output by the one before it: that constant ratio is bb.

K2 Transformed Exponential

Let g(x)=−3(2)2x−6+4g(x)=-3(2)^{2x-6}+4.

  1. a)
    Write the exponent in the form k(x−d)k(x-d). Then state aa, kk, dd and cc.
  2. b)
    State the equation of the asymptote, the domain and the range of gg.
  3. c)
    The point (2,4)(2,4) lies on y=2xy=2^x. Determine its image on gg. Then determine the yy-intercept of gg.
Stuck? Peek at a hint

Factor the 22 out of 2x−62x-6 first. A point (x,y)(x,y) maps to (xk+d, ay+c)\left(\frac{x}{k}+d,\ ay+c\right).

K3 Same Base

Solve each equation by writing both sides as powers of the same base.

  1. a)
    9x+1=27x−19^{x+1}=27^{x-1}
  2. b)
    4x=1824^{x}=\dfrac{1}{8\sqrt{2}}
  3. c)
    2x+3−2x=562^{x+3}-2^{x}=56
Stuck? Peek at a hint

Write 99, 2727, 44 and 828\sqrt{2} as powers of 33 or 22. In (c), 2x+3=8⋅2x2^{x+3}=8\cdot2^x.

K4 Evaluating Logarithms

  1. a)
    Evaluate log⁡2132\log_2\frac{1}{32}, log⁡84\log_8 4 and ln⁡e\ln\sqrt{e}.
  2. b)
    Solve log⁡x125=3\log_x 125=3 and log⁡6x=−2\log_6 x=-2.
  3. c)
    The graph of y=log⁡bxy=\log_b x passes through the marked point. Determine bb, then state the domain and range of y=bxy=b^x. Each grid square is 1 unit.
    An increasing logarithmic curve that rises steeply near the y-axis and flattens to the right, with a marked point at (9, 2).xy−1123456789−3−2123
Stuck? Peek at a hint

Rewrite each logarithm as a question: "the base to what power gives the argument?"

K5 Laws of Logarithms

  1. a)
    Evaluate log⁡64+log⁡69\log_6 4+\log_6 9 and log⁡354−log⁡32\log_3 54-\log_3 2.
  2. b)
    Write as a single logarithm: 2log⁡x+12log⁡y−3log⁡z2\log x+\frac{1}{2}\log y-3\log z.
  3. c)
    Evaluate log⁡264log⁡28\dfrac{\log_2 64}{\log_2 8} and log⁡264−log⁡28\log_2 64-\log_2 8.
Stuck? Peek at a hint

Combine first with the product or quotient law, then evaluate. Move each coefficient into the argument as a power.

Real World (A)

Growth Models · Log Scales · Solving in Context

A1 Petri Dish

A lab culture starts with 500 bacteria and doubles every 20 minutes.

  1. a)
    Write N(t)N(t), the number of bacteria after tt hours.
  2. b)
    Find the number of bacteria after 4 hours.
  3. c)
    The dish can hold about 10910^9 bacteria. When does the model reach this? Then evaluate N(24)N(24) and say what it tells you about the model.
Stuck? Peek at a hint

Count how many 20-minute periods fit in one hour.

A2 Leaf Blowers

The sound level, in decibels, of a sound with intensity II (in W/m²) is L=10log⁡(II0)L=10\log\left(\dfrac{I}{I_0}\right), where I0=10−12I_0=10^{-12} W/m².

  1. a)
    A conversation has intensity 10−610^{-6} W/m². Find its sound level.
  2. b)
    A leaf blower measures 96 dB. How many times as intense as the conversation is it?
  3. c)
    Two identical 96 dB leaf blowers run side by side. Their intensities add. Find the combined sound level.
Stuck? Peek at a hint

Subtract the two levels, divide by 10, and use the result as a power of 10.

A3 Cooling Tea

A cup of tea is left on a counter in a 20 °C room. Its temperature, in °C, after tt minutes is T(t)=20+70(0.5)t/12T(t)=20+70(0.5)^{t/12}.

  1. a)
    Find the temperature of the tea after 30 minutes.
  2. b)
    When is the tea at 50 °C?
  3. c)
    When does the tea reach 18 °C? Interpret your result.
Stuck? Peek at a hint

Isolate (0.5)t/12(0.5)^{t/12} on one side before taking logarithms.

Think It Through (T)

Building Log Functions · Error Analysis

T1 Build the Log

Each part asks for the equation of a transformed logarithmic function.

  1. a)
    The graph is a transformation of y=log⁡2xy=\log_2 x. Determine its equation in the form y=alog⁡2(x−d)+cy=a\log_2(x-d)+c. Each grid square is 1 unit.
    A decreasing curve with a dashed vertical asymptote at x = -3. It passes through the marked points (-2, 1), (-1, 0), (1, -1) and (5, -2).xy−4−3234567−3−2−112345
  2. b)
    Write the equation of a logarithmic function with vertical asymptote x=5x=5, domain (−∞,5)(-\infty,5) and xx-intercept 44.
  3. c)
    A function y=alog⁡3(x−d)+cy=a\log_3(x-d)+c has vertical asymptote x=−2x=-2 and passes through (1,5)(1,5) and (7,7)(7,7). Determine aa, dd and cc.
Stuck? Peek at a hint

Start from the asymptote: it gives dd. Then pick points where the argument is 11, 22 or 44 (or a power of 33 in (c)).

T2 Spot the Flaw

A student solves log⁡2(x+2)+log⁡2(x−4)=4\log_2(x+2)+\log_2(x-4)=4:
"Product law: log⁡2((x+2)(x−4))=4\log_2\big((x+2)(x-4)\big)=4, so (x+2)(x−4)=16(x+2)(x-4)=16. Then x2−2x−24=0x^2-2x-24=0 and (x−6)(x+4)=0(x-6)(x+4)=0. Both x=6x=6 and x=−4x=-4 are solutions."

  1. a)
    Check each claimed solution in the original equation. Which one fails, and why?
  2. b)
    State the domain of the original equation and the domain of log⁡2((x+2)(x−4))=4\log_2\big((x+2)(x-4)\big)=4. Explain how this lets the wrong root in.
  3. c)
    Another student writes log⁡2(x+2)+log⁡2(x−4)=log⁡2(2x−2)\log_2(x+2)+\log_2(x-4)=\log_2(2x-2). Use x=6x=6 to show this is false in general. Then find the only xx for which it is true.
Stuck? Peek at a hint

Substitute each value into every logarithm of the original equation, one at a time.

Boss Level

Optional challenge

A Chain of Logs

Use the change of base formula throughout.

  1. a)
    Evaluate log⁡23⋅log⁡34\log_2 3\cdot\log_3 4.
  2. b)
    Evaluate log⁡23⋅log⁡34⋅log⁡45⋯log⁡6364\log_2 3\cdot\log_3 4\cdot\log_4 5\cdots\log_{63}64.
  3. c)
    Solve log⁡2x+log⁡4x+log⁡16x=7\log_2 x+\log_4 x+\log_{16}x=7.
Stuck? Peek at a hint

Write each factor as log⁡mlog⁡b\dfrac{\log m}{\log b} and look for cancellations. In (c), express every term with log⁡2x\log_2 x.

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Answer key

Final answers only. Try first, then check.

Core Skills

K1
  • a) a=80a=80, b=14b=\frac{1}{4}
  • b) Decay; D=(−∞,∞)D=(-\infty,\infty), R=(0,∞)R=(0,\infty); asymptote y=0y=0
  • c) f(−2)=1280f(-2)=1280; f(12)=40f\left(\frac{1}{2}\right)=40
K2
  • a) g(x)=−3(2)2(x−3)+4g(x)=-3(2)^{2(x-3)}+4; a=−3a=-3, k=2k=2, d=3d=3, c=4c=4
  • b) y=4y=4; D=(−∞,∞)D=(-\infty,\infty), R=(−∞,4)R=(-\infty,4)
  • c) (4,−8)(4,-8); yy-intercept 25364≈3.95\frac{253}{64}\approx3.95
K3
  • a) x=5x=5
  • b) x=−74x=-\frac{7}{4}
  • c) x=3x=3
K4
  • a) −5-5; 23\frac{2}{3}; 12\frac{1}{2}
  • b) x=5x=5; x=136x=\frac{1}{36}
  • c) b=3b=3; y=3xy=3^x: D=(−∞,∞)D=(-\infty,\infty), R=(0,∞)R=(0,\infty)
K5
  • a) 22; 33
  • b) log⁡x2yz3\log\dfrac{x^2\sqrt{y}}{z^3}
  • c) 22; 33

Real World

A1
  • a) N(t)=500(2)3tN(t)=500(2)^{3t}
  • b) 2 048 0002\,048\,000 bacteria
  • c) After about 7.07.0 h; N(24)≈2.4×1024N(24)\approx2.4\times10^{24}, far more than the dish can hold, so the model is valid only for about the first 7 hours: growth must level off.
A2
  • a) 6060 dB
  • b) 103.6≈398110^{3.6}\approx3981 times (about 4000 times)
  • c) 96+10log⁡2≈99.096+10\log2\approx99.0 dB, not 192 dB
A3
  • a) ≈32.4\approx32.4 °C
  • b) t=12log⁡(3/7)log⁡0.5≈14.7t=\dfrac{12\log(3/7)}{\log0.5}\approx14.7 minutes
  • c) Never: (0.5)t/12=−270(0.5)^{t/12}=-\frac{2}{70} has no solution. The tea approaches room temperature, 20 °C (the asymptote), and cannot cool below it.

Think It Through

T1
  • a) y=−log⁡2(x+3)+1y=-\log_2(x+3)+1
  • b) e.g. y=log⁡(5−x)y=\log(5-x), which is y=log⁡(−(x−5))y=\log(-(x-5))
  • c) a=2a=2, d=−2d=-2, c=3c=3: y=2log⁡3(x+2)+3y=2\log_3(x+2)+3
T2
  • a) x=6x=6 works: log⁡28+log⁡22=3+1=4\log_2 8+\log_2 2=3+1=4. x=−4x=-4 fails: log⁡2(−2)\log_2(-2) is undefined, so it is extraneous.
  • b) Original: (4,∞)(4,\infty). Combined: (−∞,−2)∪(4,∞)(-\infty,-2)\cup(4,\infty). The product law widened the domain, so the combined equation accepts x=−4x=-4.
  • c) At x=6x=6: left side 44, right side log⁡210≈3.32\log_2 10\approx3.32. True only at x=2+10x=2+\sqrt{10}.

Boss Level

Boss
  • a) 22
  • b) 66
  • c) x=16x=16

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Free cheat sheet

Exponential and Logarithmic Functions Cheat Sheet

The whole unit on one page: every rule, a worked example for each idea, and the traps that cost marks.

Unit Summary

One printable page with every rule.

Build your own

The same page with blanks: fill it in from memory, then check.

Phone card

The essentials on one screen. Save it to your photos.

Most testedSolve log⁡2x+log⁡2(x−2)=3\log_2x+\log_2(x-2)=3. (card 7)

1Exponential functions

Usey=bxy=b^x, b>0b>0, b≠1b\ne1: domain R\mathbb{R}, range y>0y>0, asymptote y=0y=0, yy-intercept 11. b>1b>1 grows, 0<b<10<b<1 decays. A table has constant ratios.

Trap2−3=1/82^{-3}=1/8, still positive: the range is y>0y>0 and the curve never reaches y=0y=0.

2Exponential transformations

y=a bk(x−d)+cy=a\,b^{k(x-d)}+c: asymptote y=cy=c

UseFactor kk out of the exponent first. Map (x,y)→(x/k+d, ay+c)(x,y)\to(x/k+d,\ ay+c).

Trap22x−6=22(x−3)2^{2x-6}=2^{2(x-3)}: the shift is 33 right, not 66.

3Equal bases

UseWrite both sides as powers of the same base, then set the exponents equal. A difference like bx+3−bxb^{x+3}-b^x: factor out bxb^x.

Example4x+1=8x4^{x+1}=8^x: 22x+2=23x2^{2x+2}=2^{3x}, so x=2x=2.

Trap2x+3−2x=2x(23−1)=7⋅2x2^{x+3}-2^x=2^x(2^3-1)=7\cdot2^x, not 232^3.

4Logarithms

log⁡bx=y  ⟺  by=x\log_bx=y\iff b^y=x

Usey=log⁡bxy=\log_bx: domain x>0x>0, asymptote x=0x=0, xx-intercept 11. It is the inverse of bxb^x. log⁡\log means base 1010; ln⁡\ln means base ee.

Traplog⁡x125=3\log_x125=3 means x3=125x^3=125, so x=5x=5, not 1253125^3.

5Log transformations

y=alog⁡b[k(x−d)]+cy=a\log_b[k(x-d)]+c: asymptote x=dx=d

UseFactor kk out first. Domain: solve k(x−d)>0k(x-d)>0. The xx-intercept comes from alog⁡b[k(x−d)]+c=0a\log_b[k(x-d)]+c=0.

Trapy=log⁡(5−x)y=\log(5-x) needs 5−x>05-x>0: domain x<5x<5, not x>5x>5.

6Laws of logarithms

log⁡b(mn)=log⁡bm+log⁡bn\log_b(mn)=\log_bm+\log_bn

log⁡bmn=log⁡bm−log⁡bn\log_b\dfrac mn=\log_bm-\log_bn

log⁡bmn=nlog⁡bmlog⁡bm=log⁡mlog⁡b\log_bm^n=n\log_bm\qquad\log_bm=\dfrac{\log m}{\log b}

Traplog⁡u+log⁡v=log⁡(uv)\log u+\log v=\log(uv), never log⁡(u+v)\log(u+v).

Traplog⁡264÷log⁡28=6÷3=2\log_264\div\log_28=6\div3=2: a quotient of logs is not the log of a quotient.

7Solving with logarithms

UseExponential: isolate the power, then take log⁡\log of both sides. Log equation: condense, convert to exponential form, then check every root; each argument must be positive.

Examplelog⁡2x+log⁡2(x−2)=3\log_2x+\log_2(x-2)=3: x(x−2)=8x(x-2)=8, so x=4x=4 (x=−2x=-2 is rejected).

TrapIsolate first: 20(1.05)t=5020(1.05)^t=50 becomes 1.05t=2.51.05^t=2.5, so t=log⁡2.5/log⁡1.05≈18.8t=\log2.5/\log1.05\approx18.8.

8Models and log scales

A=A0(1+r)tA=A0(2)t/dA=A_0(1+r)^t\qquad A=A_0(2)^{t/d}

A=A0(12)t/hA=A_0\left(\dfrac12\right)^{t/h}

Usett, dd and hh in the same units. Log scales: +1+1 in pH or magnitude, or +10+10 dB, means ×10\times10. Instantaneous rate: shrink the interval.

Trap9696 dB is 103.6≈398110^{3.6}\approx3981 times as intense as 6060 dB, not 1.61.6 times.

Which strategy?

Both sides share a base Equate exponents
Bases don't match Take logs
Logs on one side Condense, convert

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