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Linear Relations Review

Try each problem first. You don’t need to finish everything.

Core path ~55 min Full sheet ~1 h 50 min

Recommended: K1–K5, then one A and one T problem

K = Knowledge & Understanding · A = Application · T = Thinking · Boss = Challenge

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Show your work on separate paper. Show your work in the dot-grid space.

Core Skills (K)

First Differences · Slope · y = mx + b · Equations of Lines · Parallel & Perpendicular

K1 Linear or Not?

For each table, use first differences to decide whether the relation is linear. If it is linear, state whether it is a direct or a partial variation and write its equation.

  1. a)
    Table (a)
    xx −2-2−1-1001122
    yy 774411−2-2−5-5
  2. b)
    Table (b)
    xx 0011223344
    yy 11225510101717
  3. c)
    Table (c)
    xx 00336699
    yy 006612121818
Stuck? Peek at a hint

First check that the xx-values go up by the same step, then subtract consecutive yy-values.

K2 Find the Slope

  1. a)
    Find the slope of the line through (−3,4)(-3,4) and (5,−2)(5,-2).
  2. b)
    Find the slope of the line through (−2,6)(-2,6) and (4,6)(4,6), and of the line through (3,−1)(3,-1) and (3,5)(3,5).
  3. c)
    Find the slope of the line graphed below. Read both axis scales.
    A rising line on a grid. The x-axis is marked every 1 unit and the y-axis every 5 units. Two marked points: (2, 10) and (6, 20).xy−11234567891015202530
Stuck? Peek at a hint

Write m=y2−y1x2−x1m=\dfrac{y_2-y_1}{x_2-x_1} with every negative coordinate in brackets. In (c), read each point's coordinates from the axis numbers.

K3 Slope and y-Intercept

  1. a)
    State the slope and yy-intercept of y=7−3xy=7-3x.
  2. b)
    State the slope and yy-intercept of 2y=x−82y=x-8.
  3. c)
    Write the equation of the line graphed below in the form y=mx+by=mx+b. Each grid square is 1 unit.
    A rising line on a 1-unit grid, crossing the x-axis to the right of the origin and the y-axis below it.xy−3−2−1124567−4−3123
Stuck? Peek at a hint

Rewrite each equation as y=…y=\dots first; mm is the number that multiplies xx. On the graph, look where the line crosses the yy-axis.

K4 Equation of a Line

  1. a)
    Determine the equation of the line with slope −3-3 that passes through (3,−4)(3,-4).
  2. b)
    Determine the equation of the line through (−2,7)(-2,7) and (4,−2)(4,-2).
  3. c)
    Write 3x−4y=123x-4y=12 in the form y=mx+by=mx+b. Then state its slope and yy-intercept.
Stuck? Peek at a hint

Substitute the point into y=mx+by=mx+b and solve for bb. In (c), subtract 3x3x from both sides, then divide every term by −4-4.

K5 Parallel & Perpendicular

  1. a)
    State the slope of a line parallel to y=−25x+1y=-\dfrac{2}{5}x+1, and of a line perpendicular to it.
  2. b)
    Determine the equation of the line perpendicular to y=4x−3y=4x-3 that passes through (8,1)(8,1).
  3. c)
    Determine the equations of the lines through (−3,2)(-3,2) that are parallel to and perpendicular to y=5y=5.
Stuck? Peek at a hint

For a perpendicular slope, flip the fraction and change its sign; write 44 as 41\frac{4}{1} first. For (c), sketch y=5y=5.

Real World (A)

Rate of Change · Linear Models · Inequalities in Context

A1 Spring Ice

In spring, the ice on a lake in Muskoka thins at a steady rate. The graph shows the ice thickness TT, in centimetres, dd days after March 15.

A falling line segment on a grid. The d-axis is marked every 4 days from 0 to 32 and the T-axis every 6 cm from 0 to 42. The segment starts at a closed point on the T-axis at (0, 36) and ends at a closed point on the d-axis at (24, 0).dT4812162028326121824303642
  1. a)
    Find the rate of change of the ice thickness. Include units, and say what the sign means.
  2. b)
    Write an equation for TT in terms of dd. How many days after March 15 is the ice 15 cm thick?
  3. c)
    The equation gives T=−9T=-9 when d=30d=30. What does this tell you about the ice on that day?
Stuck? Peek at a hint

Pick two points where the line crosses grid intersections and read their coordinates from the axis numbers.

A2 Parcel Pricing

A Winnipeg courier charges by mass. The table shows the cost CC, in dollars, to ship a parcel of mass mm, in kilograms.

m (kg)m\text{ (kg)} 2244771010
C ($)C\text{ (\$)} 1313171723232929
  1. a)
    Show that the relation is linear, and write an equation for CC in terms of mm.
  2. b)
    What do the 22 and the 99 in your equation mean? Find the cost to ship a 15 kg parcel.
  3. c)
    The courier does not ship parcels over 30 kg. A customer has $75 for one parcel. What is the heaviest parcel they can ship?
Stuck? Peek at a hint

Find the change in cost and the change in mass between each pair of neighbouring columns.

A3 Trip Fundraiser

A Grade 9 class in Thunder Bay sells pizza slices for $3 each and drinks for $2 each. They need to raise at least $600 for a trip. Let pp be the number of slices and dd the number of drinks sold.

  1. a)
    Write an inequality for the class's goal. Is its boundary line drawn solid or dashed?
  2. b)
    Do 150 slices and 70 drinks reach the goal? Do 120 slices and 120 drinks?
  3. c)
    The point (220,−30)(220,-30) satisfies your inequality. Does it describe a possible result? State the extra conditions pp and dd must meet.
Stuck? Peek at a hint

Write the money raised from pp slices and dd drinks, then compare it with $600.

Think It Through (T)

Error Analysis · Building a Rectangle

T1 Spot the Flaw

A student graphs 4x−2y>64x-2y>6:
"−2y>−4x+6-2y>-4x+6, so y>2x−3y>2x-3. I draw a solid line through (0,−3)(0,-3) with slope 22 and shade above it."
The student's boundary line is shown. Each grid square is 1 unit.

A solid rising line on a 1-unit grid, crossing the y-axis at (0, -3). The origin is marked with a point.xy−3−2−11234−5−3−2−1123
  1. a)
    Test the point (0,0)(0,0) in the original inequality. Is it a solution? Is it in the student's shaded region?
  2. b)
    Identify the student's two errors. Give the correct inequality in the form y…y\ldots and describe the correct graph.
  3. c)
    Is (2,1)(2,1) a solution of 4x−2y>64x-2y>6? Explain using the graph.
Stuck? Peek at a hint

Substitute x=0x=0 and y=0y=0 into the original inequality first.

T2 Build the Rectangle

Points A(−3,1)A(-3,1), B(1,3)B(1,3) and C(2,1)C(2,1) are plotted below. Each grid square is 1 unit.

Three labelled points on a 1-unit grid: A at (-3, 1), B at (1, 3) and C at (2, 1).xy−4−3−2−11234−3−2−11234ABC
  1. a)
    Show that ∠ABC\angle ABC is a right angle.
  2. b)
    Find point DD so that ABCDABCD is a rectangle. Then write the equation of line CDCD.
  3. c)
    A student claims: "Two lines whose slopes have opposite signs are perpendicular." Give a counterexample using a line through BB.
Stuck? Peek at a hint

Find the slopes of ABAB and BCBC first. In a rectangle, opposite sides are parallel.

Boss Level

Optional challenge

Three in a Row

The points A(1,1)A(1,1), B(3,k)B(3,k) and C(k,9)C(k,9) lie on one straight line.

  1. a)
    Find all possible values of kk.
  2. b)
    For each value of kk, write the equation of the line in the form y=mx+by=mx+b.
  3. c)
    The two lines from (b) and the xx-axis enclose a triangle. Find its area.
Stuck? Peek at a hint

On one line, the slope from AA to BB equals the slope from AA to CC.

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Answer key

Final answers only. Try first, then check.

Core Skills

K1
  • a) Linear (first differences all −3-3); partial variation; y=−3x+1y=-3x+1
  • b) Not linear: first differences 1,3,5,71, 3, 5, 7 are not constant
  • c) Linear (first differences all 66 for an xx step of 33); direct variation; y=2xy=2x
K2
  • a) m=−34m=-\dfrac{3}{4}
  • b) 00; undefined
  • c) m=52m=\dfrac{5}{2}
K3
  • a) m=−3m=-3, b=7b=7
  • b) m=12m=\dfrac{1}{2}, b=−4b=-4
  • c) y=12x−2y=\dfrac{1}{2}x-2
K4
  • a) y=−3x+5y=-3x+5
  • b) y=−32x+4y=-\dfrac{3}{2}x+4
  • c) y=34x−3y=\dfrac{3}{4}x-3; m=34m=\dfrac{3}{4}, b=−3b=-3
K5
  • a) Parallel: −25-\dfrac{2}{5}; perpendicular: 52\dfrac{5}{2}
  • b) y=−14x+3y=-\dfrac{1}{4}x+3
  • c) Parallel: y=2y=2; perpendicular: x=−3x=-3

Real World

A1
  • a) −1.5-1.5 cm per day: the ice gets 1.51.5 cm thinner each day
  • b) T=36−1.5dT=36-1.5d; 1414 days (March 29)
  • c) Nothing real: a thickness can't be negative. The ice is gone at d=24d=24, so the model only applies for 0≤d≤240\le d\le 24.
A2
  • a) The rate is 42=63=63=2\frac{4}{2}=\frac{6}{3}=\frac{6}{3}=2 dollars per kg in every interval; C=2m+9C=2m+9
  • b) $2 per kilogram; $9 fixed fee per parcel; $39
  • c) 2m+9=752m+9=75 gives m=33m=33, which is over the limit, so 30 kg (cost $69)
A3
  • a) 3p+2d≥6003p+2d\ge 600; solid
  • b) No: $590<$600\$590<\$600. Yes: exactly $600
  • c) No: the class can't sell −30-30 drinks. p≥0p\ge0 and d≥0d\ge0, and both must be whole numbers.

Think It Through

T1
  • a) 0>60>6 is false, so not a solution; but 0>−30>-3 is true, so it is in the student's region
  • b) Dividing by −2-2 must flip the sign, and >> needs a dashed line. y<2x−3y<2x-3: dashed line, shade below it.
  • c) No: 8−2=68-2=6, and 6>66>6 is false. The point lies on the dashed boundary line, which is not part of the solution.
T2
  • a) mAB=12m_{AB}=\dfrac{1}{2}, mBC=−2m_{BC}=-2, and 12×(−2)=−1\dfrac{1}{2}\times(-2)=-1
  • b) D(−2,−1)D(-2,-1); y=12xy=\dfrac{1}{2}x
  • c) e.g. y=−12x+72y=-\dfrac{1}{2}x+\dfrac{7}{2} passes through BB and has slope −12-\dfrac{1}{2}; 12×(−12)=−14≠−1\dfrac{1}{2}\times\left(-\dfrac{1}{2}\right)=-\dfrac{1}{4}\ne-1, so it is not perpendicular to ABAB.

Boss Level

Boss
  • a) k=5k=5 or k=−3k=-3
  • b) k=5k=5: y=2x−1y=2x-1; k=−3k=-3: y=−2x+3y=-2x+3
  • c) 12\dfrac{1}{2} square unit

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Free cheat sheet

Linear Relations Cheat Sheet

The whole unit on one page: every rule, a worked example for each idea, and the traps that cost marks.

Unit Summary

One printable page with every rule.

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Most testedFind the equation of the line through (−1,7)(-1,7) and (3,−5)(3,-5). (card 5)

1First differences

rate of change=ΔyΔx\text{rate of change}=\dfrac{\Delta y}{\Delta x}

Subtract consecutive yy-values:

equal steps, constant linear
equal steps, changing nonlinear
unequal xx-steps use Δy÷Δx\Delta y\div\Delta x

Examplexx: 0,2,4,60,2,4,6; yy: 5,11,17,235,11,17,23: step 22, differences 66, so y=3x+5y=3x+5.

Trapxx goes up by 22 and yy by 66: the rate is 6÷2=36\div2=3, not 66.

2Direct or partial?

UseThe yy-intercept is the starting value.

line through (0,0)(0,0) direct variation, y=mxy=mx
starts at b≠0b\ne0 partial variation, y=mx+by=mx+b

ExampleTaxi: $4 plus $2 per km, so C=2d+4C=2d+4.

TrapC=2d+4C=2d+4: 11 km costs $6, but 22 km costs $8, not $12. Only direct variation doubles.

3Slope

m=riserun=y2−y1x2−x1m=\dfrac{\text{rise}}{\text{run}}=\dfrac{y_2-y_1}{x_2-x_1}

rises left to right m>0m>0
falls left to right m<0m<0
horizontal, y=ky=k m=0m=0
vertical, x=hx=h undefined

Example(−2,5)(-2,5) and (4,−1)(4,-1): m=(−1−5)/(4−(−2))=−6/6=−1m=(-1-5)/(4-(-2))=-6/6=-1.

Trap(1,−3)(1,-3) to (4,6)(4,6): m=(6−(−3))/3=3m=(6-(-3))/3=3, not (6−3)/3=1(6-3)/3=1. Bracket negatives.

4y=mx+by=mx+b

UseIsolate yy first. Graph: plot (0,b)(0,b), then rise and run by mm. In a table, bb is yy at x=0x=0.

The line with slope 2/3 and y-intercept -1 on a grid. From the point (0, -1), a run of 3 to the right and a rise of 2 up reach the point (3, 1).xy(0, −1)(3, 1)run 3rise 2

Trapy=5−2xy=5-2x: m=−2m=-2 and b=5b=5, not m=5m=5.

5Equation of a line

UseFind mm. Put one point into y=mx+by=mx+b; solve for bb. Check the other point.

Example(−1,7)(-1,7), (3,−5)(3,-5): m=−12/4=−3m=-12/4=-3; 7=−3(−1)+b7=-3(-1)+b, so b=4b=4: y=−3x+4y=-3x+4.

Trapm=3m=3 through (2,−1)(2,-1): −1=6+b-1=6+b, so b=−7b=-7, not 22 or −1-1.

Trap2x−5y=102x-5y=10: −5y=−2x+10-5y=-2x+10; divide every term: y=0.4x−2y=0.4x-2, not 0.4x+100.4x+10.

6Parallel and perpendicular

parallel: m2=m1\text{parallel: } m_2=m_1

perpendicular: m2=−1m1\text{perpendicular: } m_2=-\dfrac{1}{m_1}

UseNegative reciprocals: product −1-1. Horizontal ⊥\perp vertical.

ExamplePerpendicular to y=3x+1y=3x+1 through (6,2)(6,2): m=−1/3m=-1/3; 2=−2+b2=-2+b, so y=−x/3+4y=-x/3+4.

TrapPerpendicular to slope 2/32/3: flip and change the sign: −3/2-3/2, not 3/23/2 or −2/3-2/3.

7Linear inequalities

UseTest a point off the line, e.g. (0,0)(0,0): true means shade its side.

Isolate yy first.

<< or >> dashed boundary
≤\le or ≥\ge solid boundary
y>y> or y≥y\ge shade above
y<y< or y≤y\le shade below

Trap−2y<4x−6-2y<4x-6: dividing by −2-2 flips the sign: y>−2x+3y>-2x+3, not y<−2x+3y<-2x+3.

8Linear models

UseSlope: rate of change, with units. bb: starting value. Extrapolate only where the situation still makes sense.

ExampleA hall costs $150 plus $12 per guest: C=12g+150C=12g+150; 4040 guests cost $630.

TrapTank: V=300−12tV=300-12t gives −60-60 L at t=30t=30. It is empty at t=25t=25, so 0≤t≤250\le t\le25.

Equation of a line: first step

Two points Slope formula
Slope and a point Solve for bb
Parallel or ⊥\perp line Same mm or −1/m-1/m

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